(arc length / (radius * 2 * pi)) * 360 = angle
-- Circumference of the circle = (pi) x (radius) -- length of the intercepted arc/circumference = degree measure of the central angle/360 degrees
The area of the sector of the circle formed by the central angle is: 37.7 square units.
The length of an arc on a circle of radius 16, with an arc angle of 60 degrees is about 16.8.The circumference of the circle is 2 pi r, or about 100.5. 60 degrees of a circle is one sixth of the circle, so the arc is one sixth of 100.5, or 16.8.
101.6 degrees = 1.7733 radians. So arc = radius*angle (in radians) = 219/2*1.7733 = 194.2 ft.
The length of an arc of a circle refers to the product of the central angle and the radius of the circle.
If the radius of a circle is tripled, how is the length of the arc intercepted by a fixed central angle changed?
(arc length / (radius * 2 * pi)) * 360 = angle
It is certainly possible. All you need is a the second circle to have a radius which is less than 20% of the radius of the first.
Central angle of a circle is the same as the measure of the intercepted arc. davids1: more importantly the formulae for a central angle is π=pi, R=radius Central Angle= Arc Length x 180 / π x R
-- Circumference of the circle = (pi) x (radius) -- length of the intercepted arc/circumference = degree measure of the central angle/360 degrees
If this is a central angle, the 72/360 x (2xpix4) = 5.024
89.52 degrees.
The area of the sector of the circle formed by the central angle is: 37.7 square units.
You can draw exactly four of the those right-angled sectors in a circle. The definition of a sector is quoted as "the portion of a circle bounded by two radii and the included arc". The circumference of a circle = 2*pi*radius. The arc of each sector will be 0.5*pi*radius.
5.23
you will need to know the angle subtended by the arc; arc length = radius x angle in radians