That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
The square root of 146
x = 0.125 ( BC - 7 )
well albert figured it out in 123 ad it equals mc2
it is the crossproducts property...right that down now...
10/3
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
8
If abcd is a parallelogram, then the lengths ab and ad are sufficient. The perimeter is 36 units.
10
let abc be the triangle with base bc. Consider it is equilateral triangle.. Now draw ad perpendicular to bc. Now ad equalls dc. Now tan 60 degree equalls ad/dc. With value of tan 60 and ad we can find dc. There fore bc equalls 2 * dc
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
For you A+ Cheaters ;D it's 50!
Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
5
The length of the hypotenuse of a right triangle if AC equals 6 and AD equals 5 is: 7.81
435