10/3
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That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
The square root of 146
There are 19 years between 10 BC and 10 AD. The reason for this is that there is no year 0 in the Gregorian calendar system, so the year following 1 BC is 1 AD. Therefore, you need to count from 10 BC to 1 AD (10 years) and then add the 9 years from 1 AD to 10 AD, totaling 19 years.
x = 0.125 ( BC - 7 )
well albert figured it out in 123 ad it equals mc2