10/3
You CAN'T calculate that, without additional information.
20
let abc be the triangle with base bc. Consider it is equilateral triangle.. Now draw ad perpendicular to bc. Now ad equalls dc. Now tan 60 degree equalls ad/dc. With value of tan 60 and ad we can find dc. There fore bc equalls 2 * dc
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
Ad < dbad < cbad + dc = cbDC + CB = DBAD < CB
10/3
10 over 3 <3 Angel
You CAN'T calculate that, without additional information.
To find the value of AD in a triangle or geometric figure labeled DC 10, you would typically need additional information, such as the lengths of other sides, angles, or relationships between the segments. If you have a diagram or specific properties (like similar triangles or the Pythagorean theorem), you could apply those principles to solve for AD. If DC represents a dimension or measurement, ensure to clarify the context for accurate calculation.
Given that AB = 8 units and AD = 10 units, we can use the ratios of corresponding sides in similar triangles to find the measure of DC. Since triangle ADC is similar to triangle ABC, the ratio of DC to AB is equal to the ratio of AD to AC. Thus, DC/8 = 10/AC. Solving for DC, DC = 8 * 10 / AC.
10!
20
let abc be the triangle with base bc. Consider it is equilateral triangle.. Now draw ad perpendicular to bc. Now ad equalls dc. Now tan 60 degree equalls ad/dc. With value of tan 60 and ad we can find dc. There fore bc equalls 2 * dc
if DC = 10 What is the measure of angle ABD?
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
value of $10 from 1928c green seal, washintong dc.
1 liter = 10 deciliters (dc)