B=c+d
Use the definition of a function. If, for any value of one variable, there is only a single possible value of the second variable, then the second variable is a function of the first variable. The second variable is often called the "dependent variable". If you can solve an equation explicitly for the dependent variable, then it is a function. If you can NOT solve it for a variable, it may or may not be a function - it turns out that some equations are hard or impossible to solve explicitly for one of the variables.
Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.
operational definition of a manipulated variable
solve x=yz for the variable y
operational definition of a manipulated variable
A variable is an alphabetic character representing a number that is not fully specified or unknown. Making algebraic computations with variables as if they were explicit numbers allows one to solve a range of problems in a single computation.
Solve the problem using the + sign for the variable. Then solve the problem using the - sign for the variable. Report your answer as the answer that you got using + or the answer that you got using -.
You replace the relevant variable with -2, and do any calculation, lookup, etc., specified in the function definition.
variable equation solve it test it
describes how to measure a variable or define a term. right out of my science book
Declaring a variable or function reserves an entry in a symbol table for that function or variable (entries in a symbol table eventually become memory addresses during linkage). Defining a variable or function actually specifies the value to be stored in the memory location specified and/or the code that should be compiled. Examples: Declaration: int foo(); // Declares a function. int bar; // Declares a variable. Definition: int foo() { printf("Hello World"); } bar = 5; Declaration and definition: int bar = 5;
Yes, that is what you are normally required to solve for.