Yes.
You can't. All you know is that 1/2 of their product is equal to the area, but you can't tell their values. There are an infinite number of triangles with different bases and heights that all have that same area.
Basically, triangles have 3 bases. Unless you want to calculate the area of the triangle(which requires the height), triangles have three bases.
To prove that two triangles with the same base and equal areas lie between the same parallels, we can use the property of area in relation to height. The area of a triangle is given by the formula ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ). Since the triangles have the same base and equal areas, their heights must also be equal. Therefore, both triangles must extend vertically to the same line, establishing that they lie between the same parallel lines.
No, because if they have different heights the area will differ between the two triangles.
If the heights and bases are the same, then the triangle is half the area of the parallelogram.
If the heights and bases are the same, then the triangle is half the area of the parallelogram.
Only if the two triangles are congruent will they have equal areas. A third fact is required to determine they are congruent (and thus have the same area): 1) The third sides are equal; 2) The angles enclosed between the sides are equal; or 3) The same one of the sides is the hypotenuse of the triangles, which are right angled triangles.
Yes, they do.
Any triangles where the base multiplied by the height equal 2, so technically, infinity.
The total area of the garden can be determined by calculating the area of one of the triangles and then multiplying that area by 6, since the garden is divided into 6 equal triangles. If the area of one triangle is known, simply multiply it by 6 to find the total area of the garden. Without the specific area of one triangle, the total area cannot be determined numerically.
only for triangles and parallelograms as far as i know
An isosceles triangle is in effect two right angled triangles joined together and in this case they have bases of 5 units and heights of 2 units so use Pythagoras' theorem to find the hypotenuse which will be the length of one of the equal legs of the isosceles triangle:- 52+22 = 29 and the square of this is about 5.385164807 or 5.385 to 3 dp