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for a vector quantity it must have both magnitude and direction and since it has both magnitude and direction it is therefore considered a vector
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
Because to completely describe it you must know both how strong it is (magnitude) and in what direction it points.
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No, the electric field oscillates in magnitude and direction as it propagates in the electromagnetic wave.
An electric field has both magnitude and direction and can be represented by lines of force, or field lines, that start on positive charges and terminate on negative charges.
for a vector quantity it must have both magnitude and direction and since it has both magnitude and direction it is therefore considered a vector
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
Electric field intensity is related to electric potential by the equation E = -dV/dx, where E is the electric field intensity, V is the electric potential, and x is the distance in the direction of the field. Essentially, the electric field points in the direction of decreasing potential, and the magnitude of the field is related to the rate at which the potential changes.
Electric field is dependent on the magnitude of the electric charge, E = qzc/r2
The magnitude of the electric field is 2.5.
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Because to completely describe it you must know both how strong it is (magnitude) and in what direction it points.
The magnitude of the electric field is 2.5.
Increase the magnitude of the electric current.
Because if you place a small object with a small electric charge in the field and release it, there's a definite direction in which it will move under the influence of the field. The direction in which a positive test-charge tries to move is defined as the direction of the electric field at that point. Since it has both a magnitude and a direction, it has all the qualifications to be recognized as a vector, and to be granted all the rights and privileges attendant thereto.