Yes, since one is a perfect square. But that's not helpful. Other than one, not every integer has a factor with an integral square root.
The square root of an integer is a CYCLOTOMIC integer.
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
No there is not. If you are looking for prime factors of a number and you get to the square root of that number you can stop. Yes, there is. If an integer is not itself a prime, then one of its factors will be less or equal to its square root and the "co-factor" will be greater than or equal to the square root. But both cannot be greater than the square root so, when searching for factors, you can stop when you reach the square root.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
Is the square root of a 100 is a integer
The square root of 3 is not an integer.
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106
No, the square root of an integer will not always be an integer. It may or may not be. The square root of nine is three, both of which are integers. The square root of two is not an integer. In fact, it is not even a rational number.
Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.
-- If the square root is an integer, then add ' 1 ' to it. -- If the square root is not an integer, then there isn't any.
The square root of 36 is 6 which is an integer.
Of course they can. Every integer greater than zero is a square root.