Q: Does the cubical expansibility depends on original volume?

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the sides of the cubical box would be 7 meters

If it is a cubical block, the volume is simply length x height x width.

This depends on what you mean by "it". The volume of the original cube is V = (80 cm)³ = 512,000 cm³. If the volume is decreased by 10%, then multiply the volume of the original cube by 0.9 to get 406,800 cm³. Otherwise, if the length of the cube is decreased by 10%, then: V = (80 cm * 0.9)³ ≈ 373248 cm³

The volume of a cube depends on the length of its edges. The formula to calculate the volume of a cube is V = s^3, where s represents the length of one side of the cube.

The new area is 22 = 4 times the original area. The new volume is 23 = 8 times the original volume.

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No. The expansivity is on a per unit basis just like the specific heat or density is.

the sides of the cubical box would be 7 meters

10

27000 mL

If it is a cubical block, the volume is simply length x height x width.

Since, this is a cubical block, It can be length * breadth* height..

The volume of an oblong is: volume = length x width x height As the box is cubical, ie is a cube, all sides are of equal length, thus: volume_cube = side x side x side = side3 So, given the volume: side = cube_root(volume) ie, take the cube root of the volume of 2.197cm3.

It is 0.015625 millilitres.

9 cause the volume is 9

To find the length of each edge of the cubical box, take the cube root of the volume. In this case, the cube root of 3.375 cubic meters is approximately 1.5 meters. Each edge of the box would be 1.5 meters in length.

No, it's not that simple. the volume of a box, if let us say (for simplicity's sake) it is cubical in shape, is the length cubed (or if it is rectangular, it is length x width x height). So let us say we have a cubical box 2' on an edge. Its volume is 2x2x2=8 cubic feet. Now let us say that we double the length of an edge. Now we have 4x4x4=64 cubic feet. It has eight times the volume of the smaller box. If we are dealing with a rectangular box rather than a cubical box, the calculations are more complicated, but it remains true that the volume grows much faster than the linear dimensions.

This depends on what you mean by "it". The volume of the original cube is V = (80 cm)³ = 512,000 cm³. If the volume is decreased by 10%, then multiply the volume of the original cube by 0.9 to get 406,800 cm³. Otherwise, if the length of the cube is decreased by 10%, then: V = (80 cm * 0.9)³ ≈ 373248 cm³