The new area is 22 = 4 times the original area.
The new volume is 23 = 8 times the original volume.
When the dimensions of a cube are doubled, each side length increases from ( s ) to ( 2s ). The surface area of a cube is calculated as ( 6s^2 ); therefore, the new surface area becomes ( 6(2s)^2 = 6 \times 4s^2 = 24s^2 ). This shows that the new surface area is four times greater than the original surface area of ( 6s^2 ). Hence, when the dimensions are doubled, the surface area indeed increases by a factor of four.
The effect on the total surface area of one dimension being doubled or tripled cannot be calculated. You either need to know all three dimensions or all three dimensions must be doubled, not just one dimension (or demension / demansion as you call them).
It quadruples.
The base areas quadruple and the curved surface doubles.
the volume increase 8 times
The effect on the total surface area of one dimension being doubled or tripled cannot be calculated. You either need to know all three dimensions or all three dimensions must be doubled, not just one dimension (or demension / demansion as you call them).
It quadruples.
If the radius of a sphere is doubled, the surface area increases by (2)2 = 4 times, and the volume increases by (2)3 = 8 times.
The base areas quadruple and the curved surface doubles.
the volume increase 8 times
The change in the surface area depends on the shape. The volume will double.
The surface area of the 'wall' doubles, but the base areas remain the same.
The surface area goes as the edge ength squared, so if you double the edges you get four times the area
The area changes by the square of the same factor.
Surface Area becomes 4 times the original when its edges are doubled because Suraface area = (edge)^2
the surface area quadruples.
The surface area is quadrupled.