Cut in half to make two trapazoids and find the area of one of the trapazoids. Don't forget to multiply the answers by two becasue you only found the area of half of the hexagon.
If you want to get really tricky or forget the trapazoid formula then cut in in sixths and find the area of a triangle. Then multiply the answer by six.
The answer to the question is at the end of the question!
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
It is not possible to answer a question given only the length of one side of a hexagon unless we are told it is a regular hexagon. I added a link that lets you calculate areas of regular polygons.
There is nothing in the question that allows you to assume that the hexagon is regular and so there is are no simple formulae. You will need to divide up the hexagon into simpler shapes. For example, pick any point inside the hexagon and join it to all the vertices. You will get six triangles. Calculate the area of each triangle and then and these areas together. Similarly, measure each side of the hexagon and add them together to get the perimeter.
The area of a hexagon with 5 centimeter sides is 64.95cm2
The answer to the question is at the end of the question!
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
The surface area of a hexagon is the same as its area. You will normally need to split the hexagon into triangles, find their area and sum these.
Area of hexagon= Area of original triangle/10
The question cannot be answered without additional information. For example, it could be a tiny hexagon, and a great big triangle.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
It is not possible to answer a question given only the length of one side of a hexagon unless we are told it is a regular hexagon. I added a link that lets you calculate areas of regular polygons.
The area of a hexagon with the perimeter of 120ft is 1,039.2ft2
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.
There is nothing in the question that allows you to assume that the hexagon is regular and so there is are no simple formulae. You will need to divide up the hexagon into simpler shapes. For example, pick any point inside the hexagon and join it to all the vertices. You will get six triangles. Calculate the area of each triangle and then and these areas together. Similarly, measure each side of the hexagon and add them together to get the perimeter.