The question cannot be answered without additional information. For example, it could be a tiny hexagon, and a great big triangle.
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The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.Click once to select an item at the bottom of the problem.
for perimeter add up the lengths of the six sides and for area divide the hexagon into six equilateral triangle, find the area of one, and multiply the product by six
the Regular hexagon : Area=(1/2)*(radius of the inscribed circle)*perimeter units2 The irregular hexagon : Area can be computed by the scalene triangle method. from one of the points to the other vertexes,you get 3 diagonals and hence three scalene triangle. hence use the area of a scalene triangle=sqrt(s (s - s1) (s - s2) (s - s3)) units2 where s=(s1+s2+s3)/2
Triangle-least area, circle- most area, per given perimeter . The circle would have an area of 154 square cm. the triangle could have an area of almost zero if it were a long, skinny triangle. An equilateral triangle would have an area approx 92.8 sq cm.
The area is 0 square units since no shaded area is visible.