Q: Factor a to the third power x to the second power minus 216x to the second power?

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simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34

x cubed minus 216

(4x - 3y)(16x^2 + 12xy + 9y^2)

3x^3(x - 4)

31

The only common factor of those two terms is the number three, giving you: 3(x3 - 8y3)

The GCF is a^2b

x(x + 1)(x - 1)

3x(x - 5)(x + 5)

27a3b2

3x

3x3 - 3x2 + 2x - 2 = 3x2(x - 1) + 2(x - 1) = (3x2 + 2)(x - 1)

The GCF is 6x^2

6x^2(2x + 5)

4 cubed is 64, 3 squared is 9, so 55.

10,077,692.

Since 14abc is a factor of 28a2b2c3, it is automatically the GCF of this problem.

-((x - 1)(2x^2 - 3x - 3))

The GCF is 2x.

GCF is 60

-8

In case you meant 64x^3 - 27y^3, that factors to (4x - 3y)(16x^2 + 12xy + 9y^2)

1

The GCF is 15x^2y^2

x4 + 2x3 - 9x2 + 18x = x(x3 + 2x2 - 9x + 18) which I do not think can be factorised further.

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