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Q: How do you factor completely x to the third power minus 216?

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3x(x - 5)(x + 5)

(x - 1)(x^2 + x + 1)

27,008

6x3

4x

Related questions

(4x - 3y)(16x^2 + 12xy + 9y^2)

3x^3(x - 4)

The only common factor of those two terms is the number three, giving you: 3(x3 - 8y3)

x(x + 1)(x - 1)

3x(x - 5)(x + 5)

a3x2 - 216x2 factors to x2(a - 6)(a2 + 6a + 36)

10,077,692.

-8

simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34

1

In case you meant 64x^3 - 27y^3, that factors to (4x - 3y)(16x^2 + 12xy + 9y^2)

Yes.

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