(2x - 3)(3x + 2)
-x^6(64x^3 - 27)
(x - 4)(3x^3 + 4) The complex roots are the cube root of negative one third times two to the two thirds power and negative two to the two thirds power divided by the cube root of three
2(x - 13)(x + 13)
(x - 5)(x - 3)
x cubed minus 216
3x(x - 5)(x + 5)
(x - 1)(x^2 + x + 1)
simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34
a3x2 - 216x2 factors to x2(a - 6)(a2 + 6a + 36)
Yes.
x(x - 1)
3x3 - 3x2 + 2x - 2 = 3x2(x - 1) + 2(x - 1) = (3x2 + 2)(x - 1)
which of the following is a factor of x2 - 5x - 6
If that equals zero, then x = 4
It is: (x-y)4
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.