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Q: Factor completely 32y4 -2x4 y4

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y4 - 256 = (y2 - 16)(y2 + 16) = (y - 4)(y + 4)(y2 + 16)

The GCF is y4

(y - 4)(y + 4)(y^2 + 16)

(2x - y2)(4x2 + 2xy2 + y4)

(y - z)(y + z)(y^2 + z^2)

x=y4 /2

(y^2 + 8)(y^2 + 2)

4x-y4 what = 0

The simplest equation would be y4 = 0

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(x2 + y2)(x + y)(x - y) = x4 - y4.

Out of that group, the GCF is 1.

The remainder is not zero so y-3 is not a factor of y^4+2y^2-4

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You need at least two terms to find a GCF. If that's y9, y4 and y8, the GCF is y4

y + y4 = y5 , possibly. Except that conventionally, the number (or coefficient) would be written first. y + y4 = y*(1 + y3) = y(1 + y)*(1 - y + y2)

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sqrt(100x4y4) = sqrt(100)*sqrt(x4)*sqrt(y4) = 10*x2*y2

y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2

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( 5x4 y4 −−−−−−√ ) ( 6x2y−−−−√ )