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Anonymous
2y4(16 - x4) = 2y4 (4 + x2)(4 - x2) = 2y4(4 + x2)(2 + x)(2 - x)
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(y^2 + 8)(y^2 + 2)
x=y4 /2
The remainder is not zero so y-3 is not a factor of y^4+2y^2-4
y4
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2