5
8.54
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What is the distance between (4, -2) and (-1,6)?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
The distance between (2,2) and (5, -1) is sqrt[(2-5)2 + (2+1)2] =sqrt(32 + 32) = sqrt(9+9) = 3*sqrt(2)
4
What is the distance between (4, -2) and (-1,6)?
What is the distance between (4, -2) and (-1,6)?
Different units for measuring distance are: 1.for distances on earth miles , kilometer, meter 2. Between galaxies - light year.
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
Points: (-6, 1) and (-2, -2) Distance: 5 units
11 points