1/2
It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
1 out of 6
If it a fair die, the probability is 1/3.
1/16
Odds against A = Probabillity against A / Probability for A Odds against A = (1 - Probabillity for A) / Probability for A 9.8 = (1 - Probabillity for A) / Probability for A 9.8 * Probability for A = 1 - Probability for A 10.8 * Probability for A = 1 Probability for A = 1 / 10.8 Probability for A = 0.0926
This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %
You cannot roll "a dice" because it is one die, many dice. If you roll an ordinary, 6 faced die, the probability that it will land on 1 is 1/6.
The probability of a fair coin to land head is 1/2. Since for 4 flips it must land heads each time, the probability of 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16.
the probability is 1 out of 6
The probability that the coin will land on heads each time is 1/2. (1/2) to the tenth power is 1/1024. This is the probability that the coin will not land on heads. Subtract it from one to get the probability that it will : 1-(1/1024)There is a 1023/1024 or about 99.90234% chance that the coin will land on heads at least once.(There is a 1/1024 chance that the coin will land on heads all four times.)
Assuming that the colors are balanced, the probability is 1 in 5.
States that to determine a probability, we multiply the probability of one event by the probability of the other event. Ex: Probability that two coins will land face heads up is 1/2 x 1/2 = 1/4 .