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It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...

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Q: If the spinner is spun twice what is the probability that the arrow will stop on an even number both times?
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What is the probability of a number less than 6 on the number cube followed by a number equal to 6 on the spinner?

The probability is(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)


Suppose the arrow is spun 50 times about how many times would you expect the spinner to lamd on an odd number?

You can expect the spinner to land an odd number 25 times out of 50.


You spin a spinner two times find the probability that the spinner stops on 3 then 1?

The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.


The spinner is divided into 12 equal parts if you spin the spinner 100 times how many times do you expect the spinner to stop on a number less than 10?

&#8729;It will be spun on a number less than 10 in 75 times if you spin it 100 times.Explanation:Let x be the random variable, x = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.The probability for any outcome is P(x) = 1/12. It is a flat probability distribution.The probability that when you spin the spinner the outcome is a number greater than10 is:P(10 &le; x &le; 12) = P(x = 10) + P(x = 11) + P(x = 12 ) = 3/12 = 1/4The probability of the complement event (that the outcome is a number smaller than 10) is: P(x < 10) = 1 - 1/4 = 3/4.So the expected number of times the spinner outcome will be a number smaller than 10 is:P(No. outcomes x


If you spin this spinner 36 times how many times would you expect it to land on 2?

The answer depends on the number of sides on the spinner and how they are numbered.

Related questions

What is the probability of a number less than 6 on the number cube followed by a number equal to 6 on the spinner?

The probability is(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)


Suppose the arrow is spun 50 times about how many times would you expect the spinner to lamd on an odd number?

You can expect the spinner to land an odd number 25 times out of 50.


suppose the arrow is spun 50 times. about how many times would you expect the spinner to land on an odd number the spinner is divided by 5?

5


If you spin the spinner two times what is the probability that the spinner will land on the black region twice?

4 of 4


You spin a spinner two times find the probability that the spinner stops on 3 then 1?

The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.


The spinner is divided into 12 equal parts if you spin the spinner 100 times how many times do you expect the spinner to stop on a number less than 10?

&#8729;It will be spun on a number less than 10 in 75 times if you spin it 100 times.Explanation:Let x be the random variable, x = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.The probability for any outcome is P(x) = 1/12. It is a flat probability distribution.The probability that when you spin the spinner the outcome is a number greater than10 is:P(10 &le; x &le; 12) = P(x = 10) + P(x = 11) + P(x = 12 ) = 3/12 = 1/4The probability of the complement event (that the outcome is a number smaller than 10) is: P(x < 10) = 1 - 1/4 = 3/4.So the expected number of times the spinner outcome will be a number smaller than 10 is:P(No. outcomes x


What is the probability that the arrow will land on either Saturday or Sunday both times?

The answer depends on where the arrow is being thrown!


If you spin this spinner 36 times how many times would you expect it to land on 2?

The answer depends on the number of sides on the spinner and how they are numbered.


What is the probability that you will spin a 4 and roll a 4?

Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) &times; Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it&rarr; pr(spin 4 & roll 4) = 2/8 &times; 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it&rarr; pr(spin 4 & roll 4) = 1/10 &times; 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it&rarr; pr(spin 4 & roll 4) = 1/10 &times; 1/6 =1/60


What is the probability of spinning a 2 on a 1-6 spinner if I spin it 60 times?

The probability of getting a 2 is 1 - (1/6)60 = 1 - 2.05*10-47


A spinner has 5 equal sections There are 3 green sections and 2 yellow sections The spinner is spun 30 times Which proportion can be used to find the number of times that the spinner lands on green?

3/5=g/30


What is the probability of two?

The answer will depend on what the experiment is: rolling a die, spinning a spinner, the number of times someone will lose before they win (or the converse), the number of rooms in a house, or whatever. Since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.