It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
The probability is(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)
You can expect the spinner to land an odd number 25 times out of 50.
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
∙It will be spun on a number less than 10 in 75 times if you spin it 100 times.Explanation:Let x be the random variable, x = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.The probability for any outcome is P(x) = 1/12. It is a flat probability distribution.The probability that when you spin the spinner the outcome is a number greater than10 is:P(10 ≤ x ≤ 12) = P(x = 10) + P(x = 11) + P(x = 12 ) = 3/12 = 1/4The probability of the complement event (that the outcome is a number smaller than 10) is: P(x < 10) = 1 - 1/4 = 3/4.So the expected number of times the spinner outcome will be a number smaller than 10 is:P(No. outcomes x
The answer depends on the number of sides on the spinner and how they are numbered.
The probability is(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)
To determine the experimental probability of the spinner landing on blue, you need to conduct a series of spins and record the outcomes. The experimental probability is calculated by dividing the number of times the spinner lands on blue by the total number of spins. For example, if the spinner is spun 100 times and lands on blue 25 times, the experimental probability would be 25/100, or 0.25.
You can expect the spinner to land an odd number 25 times out of 50.
5
To determine how many times you would expect to land on 3 after spinning the spinner 20 times, you need to know the probability of landing on 3 in a single spin. If the spinner has an equal number of sections, you can find the probability by dividing the number of sections that include 3 by the total number of sections. Multiply that probability by 20 to get the expected number of times landing on 3. For example, if the spinner has 4 equal sections, the expected number would be (20 \times \frac{1}{4} = 5).
Given, The probability of getting red, P(R) = 1/8 Red occurs by the spinner= 6 times Let, the total number of trials = N Therefore, for the experimental probability the total number of trials performed can be calculated by the following equation: P(R) = (Red occurs by the spinner)/(Total number of trials) Or, 1/8 = 6/N Or, N = 6 × 8 Or, N = 48 Final Answer: A spinner landed on red 6 times. If the resulting experimental probability of the spinner landing on red is StartFraction 1 over 8 EndFraction, then 48 trials were performed.
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.
∙It will be spun on a number less than 10 in 75 times if you spin it 100 times.Explanation:Let x be the random variable, x = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.The probability for any outcome is P(x) = 1/12. It is a flat probability distribution.The probability that when you spin the spinner the outcome is a number greater than10 is:P(10 ≤ x ≤ 12) = P(x = 10) + P(x = 11) + P(x = 12 ) = 3/12 = 1/4The probability of the complement event (that the outcome is a number smaller than 10) is: P(x < 10) = 1 - 1/4 = 3/4.So the expected number of times the spinner outcome will be a number smaller than 10 is:P(No. outcomes x
The answer depends on where the arrow is being thrown!
To determine how many times Kareen should expect to win when spinning the arrow 10 times, we need to know the probability of winning on a single spin. If, for example, the probability of winning is 0.3 (or 30%), then he can expect to win about 3 times in 10 spins (10 spins × 0.3 probability = 3 wins). Adjust the expected number of wins based on the actual probability of winning in the game.
The answer depends on the number of sides on the spinner and how they are numbered.