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14 x 3 = 42 + 14 = 56

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14y ago
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6mo ago

Let's call one of the numbers "x". Since the other number is 3 times as large as the first number, we can call it "3x". The problem states that the sum of these two numbers is 56, so we can write the equation: x + 3x = 56. Simplifying this equation gives us 4x = 56. Dividing both sides by 4 gives us x = 14. Therefore, the two numbers are 14 and 42.

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Q: Find 2 numbers who sum is 56 and such that one is 3 times as large as the other?
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