ab+40=c2
a(a+2)+40=(a+4)2
a2+2a+40=a2+8a+16
24=6a
4=a
6=b
8=c
4x6+40=82
24+40=64
64=64
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
5,6,7
11,12,13
8,10,12
5, 6 and 7
8, 9, and 10
16, 17 and 18
12, 13 and 14
1, 3, 5
14, 15, 16
4, 6, and 8
8, 10, 12