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Find an equation of variation where y varies directly as x and y 28 when x 7.?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given that ( y = 28 ) when ( x = 7 ), we can substitute these values into the equation to find ( k ): [ 28 = k(7) \implies k = 4. ] Thus, the equation of variation is ( y = 4x ).
Find an equation of variation where y varies directly as x and y equals 15 when x equals 5 find y when x equals 19?
57
If the equation of variation where y varies directly as x One pair of values is y equals 80 when x equals 40?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given the values ( y = 80 ) when ( x = 40 ), we can find ( k ) by substituting these values into the equation: ( 80 = k(40) ). Solving for ( k ) gives ( k = 2 ). Therefore, the equation of variation is ( y = 2x ).
Find an equation of variation where y varies directly as x and y 15 when x 5 find y when x is 19.?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given that ( y = 15 ) when ( x = 5 ), we can find ( k ) by substituting these values: ( 15 = k(5) ), leading to ( k = 3 ). Thus, the equation is ( y = 3x ). Now, to find ( y ) when ( x = 19 ), we substitute ( 19 ) into the equation: ( y = 3(19) = 57 ).
Find a equation of variation where y varies directly as x and y equals 0.8 when x equals 0.4?
direct variation: y = kx y = kx k = y/x = 0.8/0.4 = 2
Find an equation of variation where y varies directly as x One pair of values is y equals 80 when x equals 40?
Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
Find an equation of variation where y varies directly as x and y 28 when x 7.?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given that ( y = 28 ) when ( x = 7 ), we can substitute these values into the equation to find ( k ): [ 28 = k(7) \implies k = 4. ] Thus, the equation of variation is ( y = 4x ).
Find an equation of variation where y varies directly as x and y equals 500 when x equals 50?
y = 10x
Find an equation of variation where y varies directly as x and y equals 28 when x equals 7?
4x= y
Find an equation of variation where y varies directly as x and y equals 15 when x equals 5 find y when x equals 19?
57
Find an equation of variation where y varies directly as x and y equals 8 when x equals 2 find y when x equals 10?
40
Find an equation of variation where y varies directly as x and y equals 2 when x equals 10 find y when x equals -25?
y = -5
Find an equation of variation where y varies directly as x and y equals 10 when x equals 5 find y when x is 4?
y = 8
If the equation of variation where y varies directly as x One pair of values is y equals 80 when x equals 40?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given the values ( y = 80 ) when ( x = 40 ), we can find ( k ) by substituting these values into the equation: ( 80 = k(40) ). Solving for ( k ) gives ( k = 2 ). Therefore, the equation of variation is ( y = 2x ).
Find an equation of variation where y varies directly as x and y 15 when x 5 find y when x is 19.?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given that ( y = 15 ) when ( x = 5 ), we can find ( k ) by substituting these values: ( 15 = k(5) ), leading to ( k = 3 ). Thus, the equation is ( y = 3x ). Now, to find ( y ) when ( x = 19 ), we substitute ( 19 ) into the equation: ( y = 3(19) = 57 ).
Find a equation of variation where y varies directly as x and y equals 0.8 when x equals 0.4?
direct variation: y = kx y = kx k = y/x = 0.8/0.4 = 2
Find the variation constant and an equation of variation where y varies directly as x and y equals 10 when x equals 37?
y = kx: 10 = 37k so k = 10/37 and y = 10x/37
