0
What else can I help you with?
Find an equation of variation where y varies directly as x and y equals 500 when x equals 50?
y = 10x
A varies directly as b and a equals 12 when b equals 4 What is the constant of variation?
a varies directly as b and a = 12 when b = 4. What is the constant of variation?
If an equation of variation where y varies directly as x and y equals 15 when x equals 5 find when x equals 19?
y = 3x y = 3*19 = 57
Complete the equation of variation where y varies inversely as x and y equals 0.125 when x equals 8?
1
How would you go about solving this direct variation question and what is the answer- If P varies directly as the square of Q and the constant of variation is 6 what is the value of P when Q equals 12?
If P varies directly with the square of Q then the equation would be in the form of P = kQ2, where k is the constant of variation so the new equation would be: P = 6Q2, so when Q = 12 we have P=6*122, or P = 864
Find an equation of variation where y varies directly as x One pair of values is y equals 80 when x equals 40?
Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
Find an equation of variation where y varies directly as x and y equals 500 when x equals 50?
y = 10x
A varies directly as b and a equals 12 when b equals 4 What is the constant of variation?
a varies directly as b and a = 12 when b = 4. What is the constant of variation?
Find an equation of variation where y varies directly as x and y equals 15 when x equals 5 find y when x equals 19?
57
Find an equation of variation where y varies directly as x and y equals 8 when x equals 2 find y when x equals 10?
40
Find an equation of variation where y varies directly as x and y equals 2 when x equals 10 find y when x equals -25?
y = -5
Find an equation of variation where y varies directly as x and y equals 10 when x equals 5 find y when x is 4?
y = 8
If the equation of variation where y varies directly as x One pair of values is y equals 80 when x equals 40?
Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given the values ( y = 80 ) when ( x = 40 ), we can find ( k ) by substituting these values into the equation: ( 80 = k(40) ). Solving for ( k ) gives ( k = 2 ). Therefore, the equation of variation is ( y = 2x ).
Find a equation of variation where y varies directly as x and y equals 0.8 when x equals 0.4?
direct variation: y = kx y = kx k = y/x = 0.8/0.4 = 2
If an equation of variation where y varies directly as x and y equals 15 when x equals 5 find when x equals 19?
y = 3x y = 3*19 = 57
Find the variation constant and an equation of variation where y varies directly as x and y equals 10 when x equals 37?
y = kx: 10 = 37k so k = 10/37 and y = 10x/37
Complete the equation of variation where y varies inversely as x and y equals 80 when x equals 0.7?
2
