2, 3, 4 and 5.
consecutive means following each other so 3,4,5 are consecutive as are; 100,101,102 etc
There are no two such consecutive 'integers'!!Proof: Let the first integer be x.So, the next consecutive integer is x+1.Now, as per the question : x + (x+1) = 24=> 2x=23 (After taking all constants on one side and variable terms on the other).=> x=(23/2) = 11.5So, 11.5 & 12.5 are the required numbers but they are not integers !
This is impossible, in mathematical terms. If you take two consecutive integers, then one of the integers must be odd and the other must be even. When you add an odd number to an even number, the result is always an odd number. Here, you said two consecutive integers add up to 26, which is an even number. Therefore, the answer is "No real solutions."
Let the first integer be x. Since the consecutive integers differ by 1, the other consecutive integers would be (x + 1), (x + 2), and (x + 3). So we havex + x + 1 + x + 2 + x + 3 = 904x + 6 = 904x + 6 - 6 = 90 - 64x = 844x/4 = 84/4x = 21Thus, the third integer is 23 (21 + 2 = 23).
Let's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.
"Consecutive" integers are integers that have no other integer between them.
There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.
There are no consecutive integers that add or multiply to 224. If you meant some other binary operation, you should specify what you meant.
consecutive means following each other so 3,4,5 are consecutive as are; 100,101,102 etc
Both statements are true.These should really be asked as two separate questions.Yes, the sum of any three consecutive integers is divisible by 3. Call the first number "n", the other two will be "n + 1" and "n + 2". Adding everything together, you get 3n + 3, which is equal to 3(n + 1). Since "n" is a whole number, so is "n + 1", and 3 times as much is a multiple of 3.Two integers are consecutive if one is one more than the other... Well, yes, that's basically the definition of "consecutive".
There are no two such consecutive 'integers'!!Proof: Let the first integer be x.So, the next consecutive integer is x+1.Now, as per the question : x + (x+1) = 24=> 2x=23 (After taking all constants on one side and variable terms on the other).=> x=(23/2) = 11.5So, 11.5 & 12.5 are the required numbers but they are not integers !
Yes, the integers are 12 and 13.
You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.
There are no such numbers. If S is the sum of any 4 consecutive integers then S = 2 (mod 4) In other words, any four consecutive integers add up to an even number that is NOT dvisible by 4.
Consecutive integers mean the numbers follow one after the other. So, if you let x be an integer, then x, x+1, and x+2 are your three consecutive integers. "Sum" means they were added. So: x+(x+1)+(x+2)=237 => 3x+3 = 237 => 3x = 234 => x=78. Therefore, your integers are: 78, 79, and 80.
This is impossible, in mathematical terms. If you take two consecutive integers, then one of the integers must be odd and the other must be even. When you add an odd number to an even number, the result is always an odd number. Here, you said two consecutive integers add up to 26, which is an even number. Therefore, the answer is "No real solutions."
The larger is 114, and the other is 112.