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Find the amount of 14 percent acid solution that should be added to 6 percent acid solution to obtain 50 mL of a 12 percent solution?
Wiki User
∙ 14y ago
Write eqn for weight; x = 14% sol & y = 6% sol which is x + y = 50.
Write eqn for solution: .14x + .06y = .12*50 = 6; 2 equations 2 unknowns.
Solve: Mult 1st eqn by -.14; now -.14x-.14y = -.14*50 or -7
-.14x-.14y=-7
.14x+.06y=6
0-.08y=-1 or y=12.5 or 12.5mL of 6% solution
x+12.5=50 or x=37.5 or 37.5 mL of 14% solution
Wiki User
∙ 14y ago
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