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How many liters of a 7 percent solution of salt should be added to a 19 percent solution in order to obtain 456 liters of a 15 percent solution?
Wiki User
∙ 11y ago
This is an algebra problem. There will be 2 equations and 2 unknowns.
Let x = amount of 7% solution, and y = amount of 19% solution.
.07x + .19y = .15*456.
x + y = 456; or x = 456-y which will substitute into the first equation.
.07(456-y) +.19y = .15*456.
31.92-.07y+.19y = 68.4.
.12y = 36.48.
y = 304L (amount of 19% solution to add).
x = 456-y.
x = 456 - 304.
x = 152L (amount of 7% solution to add).
Wiki User
∙ 11y ago
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