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Let x = the amount of 20% solution

Let x + 10 = the amount of the final solution.

So we have:

(.20)x + (.50)(10) = (.40)(x + 10)

.20x + 5 = .40x + 4

.20x = 1

x = 5 liters of 20% solution of saline.

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Q: How many liters of a 20 percent solution of saline should a nurse mix with 10 liters of a 50 percent solution to obtain a mixture that is 40 percent saline?
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