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Q: Find the center and radius of the circle with this equation X2 plus Y2 minus 6X plus 2Y equals 0?

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That's the equation of a circle with its center at the origin and a radius of 8.

Centre = (0,0), the origin; radius = 11

It is the equation of a circle with radius of 6 and its center at the origin.

Radius = 1111

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2

depends on the equation.

Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2

Center of circle: (6, 8) Radius of circle: 3

If that equals 16 then the radius is 4

The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100

Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.

this is impossible

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The equation of the circle is: x^2 + y^2 = 81

x^2+y^2=36

x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5

7

9

8

x2 + y2 = 64

x² + y² = 81.

x² + y² = 4.

x2 + y2 = 81

x2 + y2 = 81