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How do you count the number of squares crossed by the diagonal in a rectangle?
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
How do you find the length of a rectangular diognal?
The length of the diagonal (not diognal), is sqrt(Length^2 + Breadth^2 + Height^2).
Find the length of the diagonal of a rectangular shaped book that has a length of 6 inches and width of 5 inches.?
To find the length of the diagonal of a rectangular book, you can use the Pythagorean theorem. The formula is (d = \sqrt{l^2 + w^2}), where (l) is the length and (w) is the width. Substituting the given values, (d = \sqrt{6^2 + 5^2} = \sqrt{36 + 25} = \sqrt{61}). Therefore, the length of the diagonal is approximately 7.81 inches.
How do I find the diagonal measurement of a rectangle with only the height of A inches and with a width-to-height ratio of 43?
To find the diagonal measurement of a rectangle with a height of A inches and a width-to-height ratio of 43, first calculate the width (W) using the ratio: ( W = 43 \times A ). Then, use the Pythagorean theorem to find the diagonal (D): ( D = \sqrt{A^2 + W^2} = \sqrt{A^2 + (43A)^2} = \sqrt{A^2(1 + 43^2)} = A \sqrt{1 + 1849} = A \sqrt{1850} ). Thus, the diagonal measurement is ( A \sqrt{1850} ) inches.
How do you find the height of a rectangular box when length is 7 m and width is 5 m and diagonal length 10m?
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
What is the length of a diagonal rectangle with a length of 9 inches and a width of 3 inches?
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
How do you count the number of squares crossed by the diagonal in a rectangle?
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
How do you find the length of a rectangular diognal?
The length of the diagonal (not diognal), is sqrt(Length^2 + Breadth^2 + Height^2).
Find the diagonal of a rectangle with 9 inches width and 6 inches length?
Using Pythagoras' theorem it is about 10.81665383 inches.
Find the length of the diagonal of a rectangular shaped book that has a length of 6 inches and width of 5 inches?
Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.
How do you find cubic inches in a box?
You find cubic inches in a box by multiplying its length by its width, and by its height. The measurements for length, width, and height should all be in inches. This is known as the volume of the box.
How do you find the length of the diagonal line in a rectangle size 10in. by 5in.?
d = 11.5 inches.
Find the length of the diagonal of a rectangular shaped book that has a length of 6 inches and width of 5 inches.?
To find the length of the diagonal of a rectangular book, you can use the Pythagorean theorem. The formula is (d = \sqrt{l^2 + w^2}), where (l) is the length and (w) is the width. Substituting the given values, (d = \sqrt{6^2 + 5^2} = \sqrt{36 + 25} = \sqrt{61}). Therefore, the length of the diagonal is approximately 7.81 inches.
How do I find the diagonal measurement of a rectangle with only the height of A inches and with a width-to-height ratio of 43?
To find the diagonal measurement of a rectangle with a height of A inches and a width-to-height ratio of 43, first calculate the width (W) using the ratio: ( W = 43 \times A ). Then, use the Pythagorean theorem to find the diagonal (D): ( D = \sqrt{A^2 + W^2} = \sqrt{A^2 + (43A)^2} = \sqrt{A^2(1 + 43^2)} = A \sqrt{1 + 1849} = A \sqrt{1850} ). Thus, the diagonal measurement is ( A \sqrt{1850} ) inches.
How do you find the cubic inches of a microwave?
You measure the inside depth, length and height and then multiply them.
What is the length of one diagonal if the base a measure 16 and the base b is 24 and has the area of 40 and a ratio of 2 is to 3?
If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
How long is the diagonal of a rectangle with dimensions 7in by 10in?
You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com
