23.............
The number is six.
GCF(280-4, 1245-3) = GCF(276, 1242) = 138
430/17=25r5 398/17=23r7
They are factors of that number
The GCF (Greatest Common Factor) of m and n is the largest positive integer that divides both m and n without leaving a remainder.
1
The number is six.
There is no such number. 1675 - 6 = 1669 which is a prime. As a result, the only number that can divide it is 1 and 1669 itself. However, 1 not only divides 1669 but it also divides 1675. That is, 1 does not leave a remainder of 6 when dividing 1675.
966 is the smallest thats all i know
GCF(280-4, 1245-3) = GCF(276, 1242) = 138
9 is the largest integer that can divide into both 36 and 81 evenly with no remainder.
430/17=25r5 398/17=23r7
They are factors of that number
The GCF (Greatest Common Factor) of m and n is the largest positive integer that divides both m and n without leaving a remainder.
138. What is required is the largest number n such that: 285 = jn + 9 1249 = kn + 7 So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276 1249 - 7 = 1242 Find hcf of 276 and 1242: 1242 / 276 = 4 r 138 276 / 138 = 2 r 0 hcf of 276 and 1242 is 138. Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
6 (leaving 6 and 7 respectively)
They are 2 and 5 leaving no remainder