There is no such number.
1675 - 6 = 1669 which is a prime. As a result, the only number that can divide it is 1 and 1669 itself.
However, 1 not only divides 1669 but it also divides 1675. That is, 1 does not leave a remainder of 6 when dividing 1675.
10698 ÷ gcf = n remainder 18 → gcf divides 10698 - 18 = 106806443 ÷ gcf = m remainder 35 → gcf divides 6443 - 35 = 640814995 ÷ gcf = k remainder 43 → gcf divides 14995 - 43 = 14952Therefore want gcf(10680, 6408, 14952) = 2136.Using prime factorization method:10680 = 2³ x 3 x 5 x 896408 = 2³ x 3² x 8914952 = 2³ x 3 x 7 x 89hcf = 2³ x 3 x 89 = 2136
... is a "factor" of the given number.
138. What is required is the largest number n such that: 285 = jn + 9 1249 = kn + 7 So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276 1249 - 7 = 1242 Find hcf of 276 and 1242: 1242 / 276 = 4 r 138 276 / 138 = 2 r 0 hcf of 276 and 1242 is 138. Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
This is a slight twist to the normal find the GCF of two numbers. In this case as a remainder of 7 is required, subtracting 7 from each number and then finding the GCF of the resulting numbers will solve the problem: 742 - 7 = 735 1162 - 7 = 1155 GCF of 1155 and 735 (using Euclid's method): 1155 / 735 = 1 r 420 735 / 420 = 1 r 315 420 / 315 = 1 r 105 315 / 105 = 3 r 0 GCF of 735 & 1155 is 105, thus 105 is the greatest number that will divide 742 and 1162 leaving a remainder of exactly 7 each time.
In mathematics, a divisor of an integer n, also called a factor of n, is an integer less than n which evenly divides n without leaving a remainder
It is: 46
46.
742/105 = 7 remainder 7 1162/105 = 11 remainder 7
1
The GCF (Greatest Common Factor) of m and n is the largest positive integer that divides both m and n without leaving a remainder.
10698 ÷ gcf = n remainder 18 → gcf divides 10698 - 18 = 106806443 ÷ gcf = m remainder 35 → gcf divides 6443 - 35 = 640814995 ÷ gcf = k remainder 43 → gcf divides 14995 - 43 = 14952Therefore want gcf(10680, 6408, 14952) = 2136.Using prime factorization method:10680 = 2³ x 3 x 5 x 896408 = 2³ x 3² x 8914952 = 2³ x 3 x 7 x 89hcf = 2³ x 3 x 89 = 2136
... is a "factor" of the given number.
23.............
As 16 divides equally by 2 without leaving a remainder, it is indeed an even number.
The greatest possible remainder for 76 is to be divided by 2 leaving the result of 38. Thank you!
A remainder of zero is obtained whenever the number is divided by its factor. For example, when 20 is divided by either 1,2,4,5,10 or 20 the remainder is zero. Every number has 1 as its divisor.Infact, this is the definition of divisor- a number which divides another number to return zero as the remainder.
A factor of a number is any number that divides into the original number evenly. That is, it divides without leaving a fraction, decimal or remainder. In this case 34 divides by 4 to give 8 remainder 2. Therefore it does not divide evenly. Thus 4 is not a factor of 34.