138.
What is required is the largest number n such that:
285 = jn + 9
1249 = kn + 7
So subtract the required remainders and then find the hcf of the results:
285 - 9 = 276
1249 - 7 = 1242
Find hcf of 276 and 1242:
1242 / 276 = 4 r 138
276 / 138 = 2 r 0
hcf of 276 and 1242 is 138.
Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
There is no such number. 1675 - 6 = 1669 which is a prime. As a result, the only number that can divide it is 1 and 1669 itself. However, 1 not only divides 1669 but it also divides 1675. That is, 1 does not leave a remainder of 6 when dividing 1675.
10698 ÷ gcf = n remainder 18 → gcf divides 10698 - 18 = 106806443 ÷ gcf = m remainder 35 → gcf divides 6443 - 35 = 640814995 ÷ gcf = k remainder 43 → gcf divides 14995 - 43 = 14952Therefore want gcf(10680, 6408, 14952) = 2136.Using prime factorization method:10680 = 2³ x 3 x 5 x 896408 = 2³ x 3² x 8914952 = 2³ x 3 x 7 x 89hcf = 2³ x 3 x 89 = 2136
... is a "factor" of the given number.
Dividing 360 by:2=1803=1204=905=729=40So the answer is yes.
All of the even numbers are divisible by 2 leaving no remainders
To find the greatest number that divides 319, 572, and 1329 while leaving remainders of 4, 5, and 6 respectively, we need to use the Chinese Remainder Theorem. First, find the least common multiple of the three given divisors (4, 5, and 6), which is 60. Then, apply the Chinese Remainder Theorem to find the number that satisfies the given conditions. The solution will be the number that is congruent to 4 modulo 4, 5 modulo 5, and 6 modulo 6.
To find the least number that divides 285 and 1249 leaving remainders of 9 and 7 respectively, we need to find the difference between the numbers and the remainders. The difference between 285 and 9 is 276, and the difference between 1249 and 7 is 1242. The least number that divides both 276 and 1242 is their greatest common divisor (GCD), which is 6. Therefore, the least number that divides 285 and 1249 leaving remainders 9 and 7 is 6.
23.............
There is no such number. 1675 - 6 = 1669 which is a prime. As a result, the only number that can divide it is 1 and 1669 itself. However, 1 not only divides 1669 but it also divides 1675. That is, 1 does not leave a remainder of 6 when dividing 1675.
It is 1 because it is the highest number that will divide evenly into both numbers leaving no remainders
It is 28 because it is the highest number that will go into both numbers evenly and leaving no remainders
It is: 46
46.
They are the numbers divisible into it and leaving no remainders.
Only 1 will go into both numbers leaving no remainders
The Greatest Common Factor of 200 and 135 is 5. There are no further divisible numbers in common, leaving you with 40 and 27 respectively
1 and 7 will go into both numbers evenly leaving no remainders