138.
What is required is the largest number n such that:
285 = jn + 9
1249 = kn + 7
So subtract the required remainders and then find the hcf of the results:
285 - 9 = 276
1249 - 7 = 1242
Find hcf of 276 and 1242:
1242 / 276 = 4 r 138
276 / 138 = 2 r 0
hcf of 276 and 1242 is 138.
Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
There is no such number. 1675 - 6 = 1669 which is a prime. As a result, the only number that can divide it is 1 and 1669 itself. However, 1 not only divides 1669 but it also divides 1675. That is, 1 does not leave a remainder of 6 when dividing 1675.
10698 ÷ gcf = n remainder 18 → gcf divides 10698 - 18 = 106806443 ÷ gcf = m remainder 35 → gcf divides 6443 - 35 = 640814995 ÷ gcf = k remainder 43 → gcf divides 14995 - 43 = 14952Therefore want gcf(10680, 6408, 14952) = 2136.Using prime factorization method:10680 = 2³ x 3 x 5 x 896408 = 2³ x 3² x 8914952 = 2³ x 3 x 7 x 89hcf = 2³ x 3 x 89 = 2136
... is a "factor" of the given number.
Dividing 360 by:2=1803=1204=905=729=40So the answer is yes.
All of the even numbers are divisible by 2 leaving no remainders
23.............
There is no such number. 1675 - 6 = 1669 which is a prime. As a result, the only number that can divide it is 1 and 1669 itself. However, 1 not only divides 1669 but it also divides 1675. That is, 1 does not leave a remainder of 6 when dividing 1675.
It is 1 because it is the highest number that will divide evenly into both numbers leaving no remainders
The GCF is 15 because it is the highest number that will divide exactly into 135 and 120 leaving no remainders.
It is 28 because it is the highest number that will go into both numbers evenly and leaving no remainders
46.
It is: 46
They are the numbers divisible into it and leaving no remainders.
Only 1 will go into both numbers leaving no remainders
The Greatest Common Factor of 200 and 135 is 5. There are no further divisible numbers in common, leaving you with 40 and 27 respectively
Factors are whole numbers that will divide into other whole numbers leaving no remainders
1 and 3 will go into both numbers evenly leaving no remainders