The GCF of 9 and 15 is 3. The LCM is 45.
Sum: 16 Product: 48 Difference: 8 Quotient: 3
forming a simultaenous equation where x+y=27 and x-y=3 you find that x=15 and y=12.
24 + 21 = 45 24 - 21 = 3 Therefore, the two numbers are 21 and 24.
3 1/2+ 6 5/8
3 + 2 = 5. (sum) 3 - 2 = 1. (difference)
The answer is 45 and 81. To find it out you need to use double algebra. 1. (x+y)-(x-y)=90 x-x=0 y+y=2y/2= 1y=y 90/2= 45 y=45 2. (x+y)+(x-y)=162 y-y=0 x+x=2x 2x/2= 1x=x 162/2=81 3. check your work x+y-x-y=90 81+45-81-45=90- x+y+x-y+=162 81+45+81-45=162 81+45= 126 81-45=36 126+36=162 That is how you find the answer.
1, 3, 5, 9, 15, 45 (sum = 78).
45/3-1, 45/3 and 45/3+1 that is, 14, 15 and 16.
45/3 - 2, 45/3 and 45/3 + 2 ie 13, 15 and 17
Two numbers with a sum of 47 are 1 and 46, 2 and 45, 3 and 44, 4 and 43, etc.
3 and 9 Difference: 9-3=6 Sum: 9+3=12