Q: Find the y-intercept of the graph y equals sin x?

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That line is [ y = 2 cos(2x) ].

the range is greater then -1 but less than 1 -1<r<1

2.9

0. sin 2x = cos 3x 1. sin 2x = sin (pi/2 - 3x) [because cos u = sin (pi/2 - u)] 2. [...]

The multiplication by 3 increases the magnitude, and the + 3 shifts the graph upward to be "centred" at y = 3. The graph now oscillates between 6 and 0 (3 + 3, 3 - 3).

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0.5

22.20366435 sin^-1(0.3779)

You could try y = 1/sin(x) but I do not see how that helps.

That line is [ y = 2 cos(2x) ].

Two thirds pi, or rather 2pi/3.

no

the range is greater then -1 but less than 1 -1<r<1

f(x) = sin(sin(x)). We don't really care about the 'x' or the '4x' or even the 'abs'. If we're looking at sin(sin(anything)), the greatest value the inside sine can have is 1, and the outer sine can't be greater than the Sin(1) which is roughly 0.8415.(assuming we're talking radians).

x = (2n+1)*pi/2 radians for any integer n.

2.9

The simplest way is to use a graphing calculator such as a TI-83. To enter in the graph do the following... 1) Hit "Y=" (It should be located in the upper left hand corner) 2) Enter the function = 4 sin (3x) Use the X,T,Theta,N button for "x" 3) Hit "Graph" Please note, make sure your calculator is in Degree Mode, and the graph is set to a "Functional" graph. To check this hit the mode button. Degree and Func should be highlighted. -------------------------------------------------------------------------- You can also draw this by hand here's how... First you need to understand the important values of sin x sin(0) = 0 sin(30) = ½ sin(60) = √3 / 2 sin(90) = 1 sin(120) = √3 / 2 sin(150) = ½ sin(180) = 0 These are important because they are part of the unit circle. Notice the repeating pattern. The important points are 0, 30, 90, 150, 180 We can plot those on a graph then we see an oscillating wave that repeats. But this would be for ƒ(x) = sin (x) Instead the 3x on the inside means we are looking for values which make our sin the same We find these by dividing the special points by 3. 0,10,30,50,60 So on those x values we will put a coordinates. Now we have to determine the y values of the coordinates. To find these we just multiply by the coefficient 4. 4 sin (3*00) = 0 4 sin (3*10) = 4/2 = 2 4 sin (3*30) = 4 4 sin (3*50) = 4/2 = 2 4 sin (3*60) = 0 Now we have our points (00,00) (10,02) (30,04) (50,02) (60,00) We plot these and then connect them on a graph to create an oscillating wave...

y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.