Two thirds pi, or rather 2pi/3.
2
Pi radians (180 degrees) is.
no
sin(0) = 0 but, in general, the sine graph need not start at 0. For example, sin(x + 2) does not start at 0.
Y=sin X is a function because for each value of X, there is exactly one Y value.
Yes, it can. If you plot theta and sin(theta) on the same graph, you will see where they intersect. I do not know of an analytical expression for this point; I think only numerical results are possible.
It is zero.
You put the acceleration on the x-axis, and sin theta on the y-axis
y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.
2
Pi
You could try y = 1/sin(x) but I do not see how that helps.
That line is [ y = 2 cos(2x) ].
The same as the period of y = sin x. This period is equal to (2 x pi).
Pi radians (180 degrees) is.
no
the period is 2pi. period is 2pi/b and the formula is y=AsinBx.