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Find the y-intercept of the graph y equals sin x?
It is zero.
What is the range of y equals -3 sin x?
sin x can have any value between -1 and 1; therefore, 3 sin x has three times this range (from -3 to 3).
What is the range for y equals x plus 2?
This is the graph of a diagnol line. Range: (-infinity, infinity)
Need help with working this Trig problem out. A sin alpha plus cos alpha equals 1 B sin alpha - cos alpha equals 1 Solution is AB equals 1?
A*sin(x) + cos(x) = 1B*sin(x) - cos(x) = 1Add the two equations: A*sin(x) + B*sin(x) = 2(A+B)*sin(x) = 2sin(x) = 2/(A+B)x = arcsin{2/(A+B)}That is the main solution. There may be others: depending on the range for x.
What is the range of y equals 3 sin x plus 3?
The multiplication by 3 increases the magnitude, and the + 3 shifts the graph upward to be "centred" at y = 3. The graph now oscillates between 6 and 0 (3 + 3, 3 - 3).
What is the range of y equals -sin x?
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
Find the y-intercept of the graph y equals sin x?
It is zero.
What is the range of y equals -3 sin x?
sin x can have any value between -1 and 1; therefore, 3 sin x has three times this range (from -3 to 3).
What is the range for y equals x plus 2?
This is the graph of a diagnol line. Range: (-infinity, infinity)
What is the range y equals - sin x?
Assuming a large enough domain, the range is -1 to 1.
How do you rewrite y equals cscx to graph it?
You could try y = 1/sin(x) but I do not see how that helps.
Need help with working this Trig problem out. A sin alpha plus cos alpha equals 1 B sin alpha - cos alpha equals 1 Solution is AB equals 1?
A*sin(x) + cos(x) = 1B*sin(x) - cos(x) = 1Add the two equations: A*sin(x) + B*sin(x) = 2(A+B)*sin(x) = 2sin(x) = 2/(A+B)x = arcsin{2/(A+B)}That is the main solution. There may be others: depending on the range for x.
What is the range of y equals 3 sin x plus 3?
The multiplication by 3 increases the magnitude, and the + 3 shifts the graph upward to be "centred" at y = 3. The graph now oscillates between 6 and 0 (3 + 3, 3 - 3).
Can cosine x equal -3?
No.-1
When does cos x equal -sin x?
The derivative of cos(x) equals -sin(x); therefore, the anti-derivative of -sin(x) equals cos(x).
Name any lines of symmetry for the graph of y equals sin x?
x = (2n+1)*pi/2 radians for any integer n.
What is the range of y equals sin2x?
range of y=sin(2x) is [-1;1] and in generally when is y=sin(k*x) (k=....-1,0,1....) range is always [-1;1] and the period is w=(2pi)/k
