Find two consecutive numbers with the value of 4160
Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.
15 and 13
11 and 12
The numbers are 8 and 9.
Let's denote the two consecutive numbers as x and x+1. The product of two consecutive numbers is given by x(x+1). We are given that x(x+1) = 6162. By solving this equation, we find that x = 78. Therefore, the two consecutive numbers are 78 and 79, as 78 * 79 = 6162.
64 x 65 = 4160
Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.
28 and 29
24,25,26
27 and 28
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
15 and 13
The numbers are 14, 15, 16 and 17.
11 and 12
The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.
27*28 = 756
They are 16 and 18