Let the two consecutive positive numbers be ( x ) and ( x + 1 ). The equation for the sum of their squares is ( x^2 + (x + 1)^2 = 164 ). Simplifying this gives ( x^2 + x^2 + 2x + 1 = 164 ), or ( 2x^2 + 2x - 163 = 0 ). Solving this quadratic equation, we find ( x = 9 ) and ( x + 1 = 10 ). Thus, the two consecutive positive numbers are 9 and 10.
12 and 14.
82 + 102 = 64 + 100 = 164
The numbers are 8 and 9.
Find two consecutive numbers with the value of 4160
169 = 144 + 25, so your numbers are 12 & 5.
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
12 and 14.
The numbers are 65 and 67.
82 + 102 = 64 + 100 = 164
The product of 2 consecutive positive number is 48. Find the 2 numbers
Ans - 7and 8
The numbers are 8 and 9.
5 and 7 52+72 = 74
Find two consecutive numbers with the value of 4160
169 = 144 + 25, so your numbers are 12 & 5.
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
Sum of squares? Product?