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Find y' of y x 2cosx?

Updated: 10/23/2022
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Q: Find y' of y x 2cosx?
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What is the derivative of x 2cosx?

For f(x) + g(x), the derivative d/dx[f(x) + g(x)] = f'(x) + g'(x). Essentially, this just means that since it's addition, you can take the derivative of each part.d/dx(x - 2cosx) =* d/dx is a way to indicate you're taking the derivatived/dx(x) + d/dx(-2cosx)* take the derivative of each part, distributing(1) + (-2*-sinx)* f(x) = x, f'(x) = 1 & g(x) = -2cosx, g'(x) = +2sinx= 1 + 2sinx


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What is the derivative of 2cosx?

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What is the derivative of 2cosx times the inverse of sinx?

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How do you find the x-intercept from a table?

You look for the value of 0 in the y column, and find out what x has to be for y=0. This value of x is you x-axis intercept. (Reverse "x" and "y" in the above description to find the y-intercept, if there is one).


How do you find x and y intercepts?

if you are looking at a graph the y intercept is when the graph crosses the y axis and the x intercept is when the graph crosses the x axis. if you have a formula... plug zero in for x to find the y intercept, and plug zero in for y to find the x intercept