The total number of outcomes is 2^5 = 32.
I believe there would be 11 possible outcomes!
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
There are eight possible outcomes: HHH, HHT, HTT, HTH, THT, TTT, TTH, THH.
If you know which coin is which, there are 16possible outcomes.If you're only counting the number of Heads and Tails, there are 5 .
9, you just have to multiply for problems like this
If a coin is tossed 15 times there are 215 or 32768 possible outcomes.
There are 25 = 32 possible outcomes.
There are 26 = 64 possible outcomes.
Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.
5 outcomes if the sequence is ignored. 24 = 16 outcomes in all.
Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.
Use Pascal's Triangle Answer is 14641 different outcomes. - - - - 1 - - - 1 - 1 - - 1 - 2 - 1 - 1 - 3 - 3 - 1 1 - 4 - 6 - 4 - 1
There are 25 or 32 possible outcomes can you get by tossing 5 coins.
If you toss eight coins, there are 256 (28) different outcomes.
There are 23 = 8 possible outcomes.
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
The answer depends on how many coins were tossed.
The theoretical probability of HT or TH when two coins are tossed is 1/2 . (All possible outcomes are HH,TT,HT,TH). This means that when we run the experiment repeatedly we expect to get the desired result 1/2 of the time. Since you intend to toss the coins 40 times, 20 are expected.
2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes.
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
There are 210 = 1024 of them.
-- 8 possibilities if the coins are different colors. -- Only 4 possibilities if you can't tell the coins apart.
There are 2^10 = 1024 of them.
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.