8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
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1/4
HHHH, HHHT, HHTT, HTTT, TTTT. Pr(HHTT) = 6/16 = 0.375
Assuming the coins are fair, two-sided coins, and landing on their sides is not an option, there are four possible outcomes if you consider coin a having a head and coin b having a tail being a different instance from coin a being a tail and coin be having a head. Here they are; Coin A | Coin B Heads | Tails Heads | Heads Tails....| Heads Tails....| Tails
false
The sample space consists of the following four outcomes: TT, TH, HT, HH