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What is the frequency of the Chess Olympiad?
at first, it was held randomly; but since the world war II, the chess olympiad has been held at a time interval of every 2 years.
How do you spell randomly?
That is the correct spelling of the word "randomly" (by chance).
Assume that women's heights are normally distributed with a mean given by mu equals 63.6 in and a standard deviation given by sigma equals 2.1 in (a) If 1 woman is randomly selected find the probabili?
To find the probability of a randomly selected woman having a height within a specific range, we can use the normal distribution with the given mean (μ = 63.6 inches) and standard deviation (σ = 2.1 inches). For instance, if we want to find the probability that a randomly selected woman is shorter than 65 inches, we would calculate the z-score using the formula ( z = \frac{(X - \mu)}{\sigma} ), where ( X ) is the height in question. After calculating the z-score, we would consult the standard normal distribution table or use a calculator to find the corresponding probability. If you have a specific height range in mind, please specify for a more detailed calculation.
A bank and loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50. If an applicant is randomly selected find the probabili?
To find the probability of a randomly selected applicant receiving a credit rating above a certain value, you would first need to determine that value. For example, if you want to find the probability of an applicant having a rating above 250, you would calculate the z-score using the formula ( z = \frac{(X - \mu)}{\sigma} ), where ( X ) is the rating, ( \mu ) is the mean (200), and ( \sigma ) is the standard deviation (50). After calculating the z-score, you can use the standard normal distribution table or a calculator to find the corresponding probability.
What is the probability of being dealt 2 aces in a 5 card poker hand?
If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.If dealt from a randomly shuffled pack it is 0.0399, approx.
YOU MEET 80 RANDOMLY SELECTED VOTERS AND FIND THAT 54% SUPPORT A CANDIDATE FOR THE LEGISLATURE OF MONAGAS. USING A CONFIDENCE LEVEL OF 95% CALCULATE THE LIMIT OF PERCENTAGE OF VOTERS WHO PREFER THE REFERRED CANDIDATE?
The confidence interval for this problem can be calculated using the following formula: Confidence Interval = p ± z*√(p*(1-p)/n) Where: p = observed proportion (54%) n = sample size (80) z = z-score (1.96) Confidence Interval = 0.54 ± 1.96*√(0.54*(1-0.54)/80) Confidence Interval = 0.54 ± 0.07 Therefore, the confidence interval is 0.47 - 0.61, meaning that we can be 95% confident that the percentage of voters who prefer the referred candidate is between 47% and 61%.
How is the standard deviation and sample variation interpreted?
Both are measures of the spread of the data around a mean or average. In fact the standard deviation == sqrt(variance). The standard deviation (SD) is defined to be the square root of the sample variance (V). EX: Some value X = M +/- 1 SD indicates that there is roughly a 2/3 probability that the value will fall randomly within the interval from minus one SD up to plus one SD around the mean M.
What is the probability that the value of a randomly selected variable from a normal distribution will be more than 3 standard deviation from its mean value?
Approx 0.0027
Vitamins to analyze the variation of vitamin supplement tablets you randomly select and weigh 14 tablets the results in milligrams are shown use 90 percent level of confidence?
To analyze the variation of vitamin supplement tablets, calculate the mean and standard deviation of the weights of the 14 tablets. With a 90% confidence level, determine the margin of error using the t-distribution. This margin of error will help define the range within which the true mean weight of the tablets is likely to lie.
The average amount customers at a certain grocery store spend yearly is 636.55 Assume the variable is normally distributed If the standard deviation is 89.46 find the probability that a randomly?
.820=82.0%
What does it mean when a boy randomly walked up to you and talked to you and kept smiling and blushing?
Either he likes you and just worked up the confidence to talk to you, in which case talk back, or his confidence will shatter, or he was dared by his friends and he doesn't really know you.
A final exam in Math 160 has a mean of 73 with standard deviation 7.8 If 24 students are randomly selected find the probability that the mean of their test scores is less than 70?
0.9699
What is the frequency of the Chess Olympiad?
at first, it was held randomly; but since the world war II, the chess olympiad has been held at a time interval of every 2 years.
What is the probability that a randomly selected ball bearing has a diameter greater than 7.4 millimeters provided that the uniform distribution over the interval is 6.8 to 8.5 millimeters.?
The probability can be calculated by finding the proportion of the interval where the diameter is greater than 7.4 mm. In this case, the proportion of the interval greater than 7.4 mm is (8.5 - 7.4) / (8.5 - 6.8) = 0.55, so the probability is 55%.
Are normally distributed with a mean of 68 inches and a standard deviation of 2 inches What is the probability that the height of a randomly selected female college basketball player is more than 66?
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
Can a USB be accessed randomly or sequentially?
Randomly
Are molecules arranged in a liquid regularly or randomly?
randomly
