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What is the probability of being dealt 2 aces in a 5 card poker hand?
Wiki User
∙ 10y ago
If dealt from a randomly shuffled pack it is 0.0399, approx.
If dealt from a randomly shuffled pack it is 0.0399, approx.
If dealt from a randomly shuffled pack it is 0.0399, approx.
If dealt from a randomly shuffled pack it is 0.0399, approx.
Wiki User
∙ 10y ago
Wiki User
∙ 10y agoIf dealt from a randomly shuffled pack it is 0.0399, approx.
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What is the probability of beind dealt five aces from a standard 52 card deck?
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
In a poker hand consisting of 5 cards find the probability of holding 3 aces?
Approximately 2%
If dealt one card from a standard 52 card deck what is the probability of being dealt an ace or a 9?
Aces and 9s are disjoint events, so the probability of either is the sum of the probabilities of each. P(A or 9) = P(A) + P(9) = 1/13 + 1/13 = 2/13
What are the odds of being dealt pocket aces in Texas hold 'em?
The odds of being dealt pocket aces in Texas hold 'em is (4 in 52) times (3 in 51) or 12 in 2652 which, reduced, is 1 in 221.
What is the probability of selecting 4 aces while playing poker with six people?
P(x=4) ≈ 0.00001847 or about 1 in 54 145The probability of selecting 4 aces while playing poker with six people is:P(x=4) = 5C4 ∙ 4!/[52!/(52-30)!] ∙ (52-4)!/(52-30)!= 5C4 ∙ 4!(52-4)!/52! ≈ 1.846892603... x 10-5 ≈ 0.00001847which is about 1 in 54 145.
What is the probability of getting dealt two aces in a deck of cards?
The odds are 220:1 of being dealt pocket aces.
What is the probability of beind dealt five aces from a standard 52 card deck?
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
What is the probability of getting exactly three aces in a five-card poker hand dealt from an ordinary 52 card deck?
The probability of getting 3 aces in the order AAABB is; P(AAABB) = (4/52)∙(3/51)∙(2/50)∙(48/49)∙(47/48) = 0.0001736... There are 5C3 = 5!/(3!∙(5-3)!) = 10 different ways in which the aces can come out. So the probability of getting exactly three aces in a five card poker hand dealt from a 52 card deck is, P(3A) ~ 10∙(0.0001736) ~ 0.001736 ~ 0.1736%
What is the probability of being dealt 4 aces from a standard 52 card deck?
The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6
You are dealt one card from a 52 deck of cards what is the probability of being an ace?
Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent
What does Pocket Rockets in poker slang mean?
it means you got dealt 2 aces from the start
The probability of being dealt 4 aces in a 5 card poker hand?
Poker hands are combinations of cards (when the order does not matter, but each object can be chosen only once.)The number 52C5 of combinations of 52 cards taken 5 at a time is (52x51x50x49x48) / (5x4x3x2x1) = 2,598,960.The number of hands which contain 4 aces is 48 (the fifth card can be any of 48 other cards.)So there is 1 chance in (2,598,960 / 48) = 54,145 of being dealt 4 aces in a 5 card hand.The odds are 54,144 to 1 against. The probabilityis 1/54145 = (approx.) 0.000018469 or 0.0018469%.
What is the combined probability of being dealt a face card and then a three as the second card from a standard 52 card deck?
Counting Aces as a face card, the answer is 0.0241 If Aces are not considered face cards, then the answer is 0.0181
In a poker hand consisting of 5 cards find the probability of holding 3 aces?
Approximately 2%
What is the probability you will be dealt 2 aces from a standard 52-card deck?
The probability is 4/52 for the first ace and 3/51 for the second. So the probability of 2 aces is 4/52 x 3/51 = 1/221
If dealt one card from a standard 52 card deck what is the probability of being dealt an ace or a 9?
Aces and 9s are disjoint events, so the probability of either is the sum of the probabilities of each. P(A or 9) = P(A) + P(9) = 1/13 + 1/13 = 2/13
What is something you like that starts with the letter a?
I like to be dealt aces when I play poker. I like animals and artwork. I like to eat artichoke and avocado.
