It is not possible to solve the above equation because it is not clear.
2x = 3x + 1; -x = 1; x = -1.
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
The product of (3x-1)(x+5) = 3x^2 +14x -5 by multiply out the brackets
-3x + 1
3 * 3 + 1 = 10
f x 3x plus 1 and g x x 2 -6 find fog 4 can not be solved.
2x = 3x + 1; -x = 1; x = -1.
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
The product of (3x-1)(x+5) = 3x^2 +14x -5 by multiply out the brackets
3x + 11
If that's -9x^3 - 3x^2 + 3x + 1, that factors to (1 - 3x^2)(1 + 3x)
x=-11
2x2 + 3x + 1 = (x + 1)(2x + 1)
-3x + 1
3 * 3 + 1 = 10
(-3x - 1)(3x - 7)