f x 3x plus 1 and g x x 2 -6 find fog 4 can not be solved.
You cannot add 3x and 1. You can add 3x and x and get 4x though.
2x+x+5+3x-6=6x-1
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
12x2 + 7x + 1 = 12x2 + 3x + 4x + 1 = 3x*(4x + 1) + 1*(4x + 1) = (4x + 1)*(3x + 1)
3x+y=-1 y=-1-3x5x-y=9 5x-(-1-3x)=95x+1+3x=98x=8x=1y=-1-3(1)y=-4(1,-4)
It is not possible to solve the above equation because it is not clear.
2x = 3x + 1; -x = 1; x = -1.
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
The product of (3x-1)(x+5) = 3x^2 +14x -5 by multiply out the brackets
3x + 11
If that's -9x^3 - 3x^2 + 3x + 1, that factors to (1 - 3x^2)(1 + 3x)
2x2 + 3x + 1 = (x + 1)(2x + 1)
x=-11
-3x + 1
(-3x - 1)(3x - 7)
3 * 3 + 1 = 10