9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
3(x2 + 3x + 1)
3x2 + 10x + 3 = (x + 3)(3x + 1).
(3x+1)(x+2)
(3x + 1)(x + 6)
(-3x - 1)(3x - 7)
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
3x(2y + 1)
3(x2 + 3x + 1)
(3x + 1)(x + 5)
(x + 5)(3x + 1)
3x(56x2-15x+1)
3x(2x + 1)
(x + 2)(3x - 1)(3x + 1)
168x3 - 45x2 + 3x = 3x(56x2 - 15x + 1) = 3x(7x - 1)(8x - 1)
You notice the first two items, 3bx + 3x factorizes into 3x(b+1). And the last two, by +y factorize into y(b+1) . So (b+1) is a common factor, so you can factorize these two into (b+1)(3x+y)
(-3x+1)(-2x+1)