The number of diagnol formed by a convex polygon having N sides is {N*(N-1)/2} - N .
360 degrees. The sum of the measures of the exterior angles any convex polygon will always be 360 degrees. The formula for finding the sum of the measures of the interior angles is 180(n-2) when n= the total number of sides the polygon has.
add all the sides ???
it has four sides
The sum of the interior angles of a triangle is 180 deg. For a convex polygon with n sides we can divide it to n-2 triangles. So the answer, if the polygon is convex, is (13-2)*180= 1980 deg * * * * * The polygon need not be convex. The formula for the sum of the interior angles is valid as long as the polygon is simple - that it, its sides do not cross each other inside the polygon.
By using the polygon diagonal formula or the quadratic equation formula in which in both formulae they work out that the polygon in question has 21 sides.
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
Not necessarily. A convex heptagon is a polygon but it need not have all sides and angles congruent.
The formula for finding the sum of all angles of a polygon is: N = number of sides (N-2)180 = The sum of all angles
1/2*(n2-3n) where n is the number of sides of the polygon
It is a regular polygon.
The answer depends on the number of sides in the polygon.
(number of sides-2)*180 = sum of interior angles of a polygon