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He perimeter of a rectangle is 58 m. If the width were doubled and the length were increased by 10 m the perimeter would be 92 m. What are the length and width of the rectangle?
Wiki User
∙ 12y ago
2x+2y=58
2(x+10)+4y=92
now you just solve one of these in terms of y or x, so the first one would be
2x+2y=58
2x=58-2y
x=29-y
and you plug that in for x into the second equation
2((29-y)+10)+4y=92
58-2y+20+4y=92
2y=14
y=7 (this is the width)
and you can plug this y back into what you got for x
x=29-y
x=22
so length is 22 width is 7
Wiki User
∙ 12y ago
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