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Hooke's law if a 3 kg mass stretches a spring 40 cm how far will a 5 kg mass stretch the spring?
Wiki User
∙ 14y ago
The first step here is to find the spring constant. Use Hooke's law and the information given about the 3 kg mass:
F=kx
F=w3kg-mass=m3kg-massg=(3 kg)(9.8 m/s2)
(3 kg)(9.8 m/s2)=(.40 m)k
k=[(3 kg)(9.8 m/s2)/(.40 m)]
Now plug that in (I don't have a calculator handy, and some of the units and numbers there will cancel, so I didn't bother to calculate it out) to Hooke's law for the 5 kg mass:
F=kx
F=w5kg-mass=m3kg-massg=(5 kg)(9.8 m/s2)
(5 kg)(9.8 m/s2)=kx
(5 kg)(9.8 m/s2)=[(3 kg)(9.8 m/s2)/(.40 m)]x
x=2/3 m
The 5 kg mass would stretch the spring two thirds of a meter.
Wiki User
∙ 14y ago
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